(A) 36
(B) 72
(C) 144
(D) 532
Correct Option is: A
There are 6 different letters in the given word, out of which there are 3 vowels and 3 consonants.
Let us mark these positions as under:
[1] [2] [3] [4] [5] [6]
Now, 3 vowels can be placed at any of the three places out of 3 marked 1, 3 and 5.
Number of ways of arranging the vowels = 3P3
= 3!
= 6 ways.
Also, the 3 consonants can be arranged at the remaining 3 positions.
Number of ways of these arrangements = 3P3
= 3!
= 6 ways.
Therefore, total number of ways = 6 x 6 = 36.