The ages of two sisters differ by 32 years. 12 years ago, the elder one was 7 times as old as the younger one. What are their present ages of the elder person?

(A) 42.7
(B) 45.4
(C) 46.9
(D) 49.3

The sum of the current ages of a father and his son is 84 years. 7 years ago, father’s age was 3 times the age of the son. After 7 years, son’s age will be?

(A) 28 Years
(B) 35 Years
(C) 53 Years
(D) 58 Years

The sum of the ages of a Mother and son is 54 years. Eight years ago, the product of their ages was 6 times the mother’s age at that time. The present age of mother and son is?

(A) 14,40
(B) 34,17
(C) 40,14
(D) 50,17

12 years ago M was half of N in age. If the ratio of their present ages is 4 : 5, what will be the total of their present ages?

(A) 30
(B) 32
(C) 35
(D) 36

The father age 7 years ago was 11 times the age of his daughter. At present the father age is 7 times that of his daughter. Find the daughter present age.

(A) 17.5
(B) 18.2
(C) 23
(D) 25.4

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