How many different 4 persons teams can be made from a group of 9 players?

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• A taxi driver make a trip from the plains to ooty which are 340 km apart at an average speed of 60 km/hr. In the return trip, he covers the speed distance at an average of 30 km/hr. The average speed of the taxi over the entire distance of 680 km is:

  (A) 30 km/hr
  (B) 40 km/hr
  (C) 50 km/hr
  (D) 60 km/hr

  ►Correct Option
  
  Correct Option is: B
  Average speed =(2xy/( x+y)) km/hr
  Given x =60 km/hr y = 30km/hr
  Average speed = (2*60*30/ (60+30)) km/hr
  =(3600/ 90)
  =40 km/hr
  

• Anitha takes 8 hours 20 mints in walking to a temple and riding back. She would have gained 3 hours by riding both ways. The time she would take to walk both ways is:

  (A) 15 hours 40 mints
  (B) 16 hours 40 mints
  (C) 18 hours 40 mints
  (D) 19 hours 40 mints

  ►Correct Option
  
  Correct Option is: D
  Let the distance be x km. then,
  (time taken to walk x km)+(time taken to ride x km) = 25/3 hrs
  (time taken to walk 3x km)+(time taken to ride 3x km) = 25/3*3 =25hrs
  But the time taken to ride 3xkm=(25/3 – 3)hrs
  =(25 – 9)/3 hrs
  =16/3 hrs
  Time taken to walk 3x km = (25 – 16/3)hrs
  =(75 – 16)/3
  =59/3
  =19 hours 40 mins
  

• Jackson travels a distance of 100 km in 5 hours. How much faster in kilometer per hour, on an average, must he travel to make a journey in 5/3 hour less time?

  (A) 5 km/hr
  (B) 6 km/hr
  (C) 8 km/hr
  (D) 10 km/hr

  ►Correct Option
  
  Correct Option is: D
  Time required = (5 hrs – 5/3 hrs)
  =(5 hrs – 100 mints)
  = (5 hrs – 1hr 40 mints)
  = 3 hrs 20 mints
  = 3 1/3 hrs
  Required speed = (100*3/10) km/hr
  =30 km/hr
  Original speed = (100/5)km/hr = 20 km/hr
  Difference speed = required speed – original speed
  =(30-20)
  =10km/hr
  

• A royal enfield bike starts with the speed of 210 km/hr with its speed increasing every 2 hours by 30 km/hr, in how many hours will it cover 1035 km?

  (A) 2 1/2 hour
  (B) 4 1/2 hour
  (C) 6 1/2 hour
  (D) 7 1/2 hour

  ►Correct Option
  
  Correct Option is: B
  Distance covered in 1st 2 hrs = (210*2)km
  =420km
  Distance covered in next 2 hrs = (240*2)km
  =480km
  Remaining distance = 1035 – (420+480)
  =1035 – 900
  =135km
  Speed in 5th hr = 270 km/hr
  Time taken to cover 135 km = 135/270 = ½ hr
  Total time taken = (2+2+1/2)
  =4 ½ hrs
  

• A hare is spotted by a tiger from a distance of 50 metres. When the tiger starts a chase, the hare also starts running. If the speed of the hare be 4 km/hr and that of a tiger 5 km/hr, how far the hare will have run before its over taken?

  (A) 100 m
  (B) 200 m
  (C) 300 m
  (D) 400 m

  ►Correct Option
  
  Correct Option is: B
  Relative speed of the tiger = (5-4)km/hr
  =1 km/hr
  Time taken by tiger to cover 50 m,
  =(50/1000)hr =1/20hr
  In 1/20 hrs, the tiger cover a distance of (4*1/20)km
  =1/5km =>(1/5*1000)m
  =200m
  

• A monkey takes 16 jumps for every 20 jumps of a dog but 12 jumps of a monkey are equal to 16 jumps of the dog. Compare their speeds?

  (A) 15:16
  (B) 17:16
  (C) 16:15
  (D) 16:17

  ►Correct Option
  
  Correct Option is: C
  Let the distance covered in 1 jump of the monkey be x and,
  Distance covered in 1 jump of the dog be y
  Then 12 x = 16y
  X = 16 / 12 y ———->1
  Ratio of speed of monkey and dog = Ratio of distances covered by them in the same time
  =16x : 20y
  =256 /12 y : 20y (from 1)
  =256 : 240
  = 16:15
  
  

• John leaves New York at 3 am and reaches Texas at 11 am . Michael leaves Texas at 5 am and reaches New York at 12:00 noon. At what time do they cross each other?

  (A) 7 : 52 AM
  (B) 8 : 25 AM
  (C) 6 : 52 AM
  (D) 9 : 25 AM

  ►Correct Option
  
  Correct Option is: C
  Time taken by John = 8 h
  Time taken by Michael = 7 h
  For your convenience take the product of times taken by both as a distance.
  Then the distance = 56km
  Since, John covers half of the distance in 2 hours(i.e at 5 am)
  Now, the rest half (i.e 28 km) will be coverd by both Michael and John
  Time taken by them = 28/15 = 1 hr 52 min
  Thus , they will cross each other at 6 : 52 AM
  

• A passenger train without stopping running at an average speed of 120 km/hr and with stoppages at an average speed of 80 km/hr. What is the total time taken by the train for stoppages on a route of length 480km?

  (A) 2 Hours
  (B) 3 Hours
  (C) 4 Hours
  (D) 5 Hours

  ►Correct Option
  
  Correct Option is: A
  Let r = running time of the train
  s= stoppage time of the train
  D= total distance travelled by train
  We have:
  D/r= 120 and………..(1)
  D/(r+s) =80………..(2)
  Diviving (1)&(2),
  D/r *(r+s)/D = 120/80
  (r+s)/r =3/2
  1 +s/r =3/2
  s/ r = 3/2-1
  s/ r = ½……………(3)
  As, D=480 kms
  480/r= 120
  r=4
  put r value in (3),we get
  s/4 =1/2
  S = 2 hours