(A) 24
(B) 120
(C) 840
(D) 5040
Correct Option is: C
There are 7 different letters in the word ‘ABOLISH’.
Therefore,
The number of arrangements of any 4 out of seven letters of the word = Number of all permutations
of 7 letters, taken 4 at a time =
nPr = n(n – 1)(n – 2) … (n – r + 1)
Here, n = 7 and r = 4, then we have
7p4 = 7 x 6 x 5 x 4 = 840.
Hence, the required number of ways is 840.